What is the derivative of 2/(x^{1/3)}-2 ?

The derivative of 2/(x^{1/3)}-2 is -2/(3x^{4/3)}

What is the first derivative of 2/(x^{1/3)}-2 ?

The first derivative of 2/(x^{1/3)}-2 is -2/(3x^{4/3)}

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derivative of

\frac{2}{x ^{\frac{1}{3}}} - 2

- \frac{2}{3 x ^{\frac{4}{3}}}

Solution steps

\frac{d}{d x} (\frac{2}{x ^{\frac{1}{3}}} - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{2}{x ^{\frac{1}{3}}}) - \frac{d}{d x} (2)

\frac{d}{d x} (\frac{2}{x ^{\frac{1}{3}}}) = - \frac{2}{3 x ^{\frac{4}{3}}}

\frac{d}{d x} (2) = 0

= - \frac{2}{3 x ^{\frac{4}{3}}} - 0

Simplify

= - \frac{2}{3 x ^{\frac{4}{3}}}

2 y^{^{'}} + t y = 7

\frac{d}{d x} (\frac{3 x - 1}{2 x + 5})

y = 4 x^{2}, y^{2} = \frac{1}{4} x

y^{^{''}} - x^{2} + y^{^{'}} = 0

\int \frac{1 - x ^{2}}{x} d x

What is the derivative of 2/(x^{1/3)}-2 ?
The derivative of 2/(x^{1/3)}-2 is -2/(3x^{4/3)}
What is the first derivative of 2/(x^{1/3)}-2 ?
The first derivative of 2/(x^{1/3)}-2 is -2/(3x^{4/3)}