What is the tangent of y=sec(x),(pi/6 ,(2sqrt(3))/3) ?

The tangent of y=sec(x),(pi/6 ,(2sqrt(3))/3) is y= 2/3 x+2/(sqrt(3))-pi/9

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tangent of y=sec(x),(pi/6 ,(2sqrt(3))/3)

tangent of

y = sec (x), (\frac{π}{6}, \frac{2 3}{3})

y = \frac{2}{3} x + \frac{2}{3} - \frac{π}{9}

Solution steps

Find the slope of

y = sec (x) : \frac{d y}{d x} = sec (x) tan (x)

Compute the slope of

y = sec (x)

(\frac{π}{6}, \frac{2 3}{3}) : m = \frac{2}{3}

Find the line with slope m=

\frac{2}{3}

and passing through

(\frac{π}{6}, \frac{2 3}{3}) : y = \frac{2}{3} x + \frac{2}{3} - \frac{π}{9}

y = \frac{2}{3} x + \frac{2}{3} - \frac{π}{9}

2 x y^{^{'}} - 8 y = x^{- 4}

- \frac{1}{2 1 - x}

\int 1 + t^{4} d t

t \to 0 lim (e^{- 6 t})

\int \frac{x ^{2} - 16}{x ( x + 2 ) ^{3}} d x

What is the tangent of y=sec(x),(pi/6 ,(2sqrt(3))/3) ?
The tangent of y=sec(x),(pi/6 ,(2sqrt(3))/3) is y= 2/3 x+2/(sqrt(3))-pi/9