What is the derivative of (ax+b^n) ?

The derivative of (ax+b^n) is n(ax+b)^{n-1}a

What is the first derivative of (ax+b^n) ?

The first derivative of (ax+b^n) is n(ax+b)^{n-1}a

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\frac{d}{d x} ((a x + b)^{n})

n (a x + b)^{n - 1} a

Solution steps

\frac{d}{d x} ((a x + b)^{n})

Apply the chain rule:

n (a x + b)^{n - 1} \frac{d}{d x} (a x + b)

= n (a x + b)^{n - 1} \frac{d}{d x} (a x + b)

\frac{d}{d x} (a x + b) = a

= n (a x + b)^{n - 1} a

f (x) = \frac{x ^{2}}{2} + 2 x + 4

f^{^{'}} (x) = \frac{9}{2 9 x - 5}

\int \frac{1}{x ^{2} 25 - x ^{2}} d x

x \cdot (ln (x))^{2}

\int sin (x) + cos (y) d x

What is the derivative of (ax+b^n) ?
The derivative of (ax+b^n) is n(ax+b)^{n-1}a
What is the first derivative of (ax+b^n) ?
The first derivative of (ax+b^n) is n(ax+b)^{n-1}a