What is the limit as x approaches 0 of sin(x)-e^x ?

The limit as x approaches 0 of sin(x)-e^x is -1

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limit as x approaches 0 of sin(x)-e^x

x \to 0 lim (sin (x) - e^{x})

- 1

Solution steps

x \to 0 lim (sin (x) - e^{x})

Plug in the value

x = 0

= sin (0) - e^{0}

Simplify

sin (0) - e^{0} : - 1

= - 1

\frac{d y}{d t} - 2 t y = - 12 t^{2} e^{t^{2}}, y (0) = - 1

\int (ln (4 x))^{2} d x

\int_{2}^{4} 1 - (x - 3)^{2} d x

\frac{\partial}{\partial x} (6 q (r, t, x)^{2} + 7 r^{3} - \frac{8}{t} - q (r, t, x) t)

y y^{^{'}} + x = 0

What is the limit as x approaches 0 of sin(x)-e^x ?
The limit as x approaches 0 of sin(x)-e^x is -1