What is (\partial)/(\partial x)(sin(8x)cos(2y)) ?

The answer to (\partial)/(\partial x)(sin(8x)cos(2y)) is cos(2y)cos(8x)*8

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(\partial)/(\partial x)(sin(8x)cos(2y))

\frac{\partial}{\partial x} (sin (8 x) cos (2 y))

cos (2 y) cos (8 x) \cdot 8

Solution steps

\frac{\partial}{\partial x} (sin (8 x) cos (2 y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (2 y) \frac{\partial}{\partial x} (sin (8 x))

Apply the chain rule:

cos (8 x) \frac{\partial}{\partial x} (8 x)

= cos (8 x) \frac{\partial}{\partial x} (8 x)

\frac{\partial}{\partial x} (8 x) = 8

= cos (2 y) cos (8 x) \cdot 8

\int_{1}^{4} x \cdot ln (x) d x

\frac{d}{d x} (\frac{x ^{3}}{3} + \frac{8}{3} - x^{2} + 4)

y^{^{''}} - 4 y^{^{'}} + 5 y = 0, y (0) = 1, y^{^{'}} (0) = 0

y^{^{'}} = 6 x

\frac{d}{d x} (- x^{2} + 2 x + 1)

What is (\partial)/(\partial x)(sin(8x)cos(2y)) ?
The answer to (\partial)/(\partial x)(sin(8x)cos(2y)) is cos(2y)cos(8x)*8