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Popular >

y^'=xe^{x-y}

Solution

y^{^{'}} = x e^{x - y}

Solution

y = ln (e^{x} x - e^{x} + c_{1})

Solution steps

y^{'} (x) = x e^{x - y}

Solve separable ODE:

y = ln (e^{x} x - e^{x} + c_{1})

y = ln (e^{x} x - e^{x} + c_{1})

Popular Examples

limit as x approaches 50 of x+10

x \to 50 lim (x + 10)

integral of (e^{-x})/(sqrt(1-e^{-2x))}

\int \frac{e ^{- x}}{1 - e ^{- 2 x}} d x

integral of (sqrt(r)+3)/(r+3)

\int \frac{r + 3}{r + 3} d r

(d^4)/(dx^4)(xe^{5x}cos(2x))

\frac{d ^{4}}{d x ^{4}} (x e^{5 x} cos (2 x))

integral from-2pi to-(5pi)/2 of 5cos(x)

\int_{- 2 π}^{- \frac{5 π}{2}} 5 cos (x) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=xe^{x-y} ?
The solution for y^'=xe^{x-y} is y=ln(e^xx-e^x+c_{1})