What is the solution for 9(t+1)((dy)/(dt))-6y=18t ?

The solution for 9(t+1)((dy)/(dt))-6y=18t is y=6t+c_{1}(t+1)^{2/3}+9

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9(t+1)((dy)/(dt))-6y=18t

9 (t + 1) (\frac{d y}{d t}) - 6 y = 18 t

y = 6 t + c_{1} (t + 1)^{\frac{2}{3}} + 9

Solution steps

9 (t + 1) (\frac{d y}{d t}) - 6 y = 18 t

Solve linear ODE:

y = 6 t + c_{1} (t + 1)^{\frac{2}{3}} + 9

y = 6 t + c_{1} (t + 1)^{\frac{2}{3}} + 9

\frac{x ^{2} - 4 x}{( x - 2 ) ^{2}}

\int \frac{2 ^{(18 x)}}{4} d x

\int 2 x x d x

\frac{d}{d x} ((9 x^{3} + 3 x^{2})^{4})

- y^{^{'}} - 5 y = - t

What is the solution for 9(t+1)((dy)/(dt))-6y=18t ?
The solution for 9(t+1)((dy)/(dt))-6y=18t is y=6t+c_{1}(t+1)^{2/3}+9