What is the solution for y^{''}+3(y^')^2=-17 ?

The solution for y^{''}+3(y^')^2=-17 is y= 1/3 ln(cos(sqrt(51)(c_{1}+t)))+c_{2}

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y^{''}+3(y^')^2=-17

y^{^{''}} + 3 (y^{^{'}})^{2} = - 17

y = \frac{1}{3} ln (cos (51 (c_{1} + t))) + c_{2}

Solution steps

y^{''} (t) + 3 (y^{'} (t))^{2} = - 17

Solve using substitution:

y = \frac{1}{3} ln (cos (51 (c_{1} + t))) + c_{2}

y = \frac{1}{3} ln (cos (51 (c_{1} + t))) + c_{2}

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\int - 3 y^{2} d y

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\frac{\partial}{\partial x} ((x - 1)^{2})

What is the solution for y^{''}+3(y^')^2=-17 ?
The solution for y^{''}+3(y^')^2=-17 is y= 1/3 ln(cos(sqrt(51)(c_{1}+t)))+c_{2}