What is the integral from 1 to infinity of 10e^{-5x} ?

The integral from 1 to infinity of 10e^{-5x} is 2/(e^5)

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integral from 1 to infinity of 10e^{-5x}

\int_{1}^{\infty} 10 e^{- 5 x} d x

\frac{2}{e ^{5}}

Decimal Notation

0.01347 \dots

Solution steps

\int_{1}^{\infty} 10 e^{- 5 x} d x

Compute the indefinite integral:

\int 10 e^{- 5 x} d x = - 2 e^{- 5 x} + C

Compute the boundaries:

\int_{1}^{\infty} 10 e^{- 5 x} d x = 0 - (- \frac{2}{e ^{5}})

= 0 - (- \frac{2}{e ^{5}})

Simplify

= \frac{2}{e ^{5}}

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What is the integral from 1 to infinity of 10e^{-5x} ?
The integral from 1 to infinity of 10e^{-5x} is 2/(e^5)