What is the sum from n=0 to infinity of ne^{-8n} ?

The sum from n=0 to infinity of ne^{-8n} is converges

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sum from n=0 to infinity of ne^{-8n}

n = 0 \sum \infty n e^{- 8 n}

converges

Solution steps

n = 0 \sum \infty n e^{- 8 n}

Apply Series Ratio Test:

converges

= converges

\frac{\partial}{\partial x} (e^{2 x - 3 y})

\frac{d}{d x} ((\frac{x ^{2} + 3}{x ^{2} - 3})^{4})

\frac{\partial}{\partial x} (\frac{x}{A})

\frac{d}{d x} (a cos^{3} (t))

n \to \infty lim (n - \frac{1}{n})

What is the sum from n=0 to infinity of ne^{-8n} ?
The sum from n=0 to infinity of ne^{-8n} is converges