What is the limit as t approaches 0 of 5/(1+t) ?

The limit as t approaches 0 of 5/(1+t) is 5

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limit as t approaches 0 of 5/(1+t)

t \to 0 lim (\frac{5}{1 + t})

5

Solution steps

t \to 0 lim (\frac{5}{1 + t})

Plug in the value

t = 0

= \frac{5}{1 + 0}

Simplify

= 5

y^{^{''}} - 3 y^{^{'}} = 18 t + 26 sin (2 t)

y^{^{''}} + 16 y = 32 sin (4 t)

\frac{d}{d x} (\frac{2}{3} x + \frac{4}{3 x ^{2}})

\frac{d}{d x} (f (x) \circ g (x))

x \to 1 - lim (\frac{x ^{3} - 1}{x - 1})

What is the limit as t approaches 0 of 5/(1+t) ?
The limit as t approaches 0 of 5/(1+t) is 5