What is the integral of e^{-0.04x} ?

The integral of e^{-0.04x} is -25e^{-0.04x}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{-0.04x}

\int e^{- 0.04 x} d x

- 25 e^{- 0.04 x} + C

Solution steps

\int e^{- 0.04 x} d x

Apply u-substitution

: \int - \frac{1}{0.04} e^{u} d u

= \int - \frac{1}{0.04} e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{0.04} \cdot \int e^{u} d u

Simplify

= - 25 \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= - 25 e^{u}

Substitute back

u = - 0.04 x

= - 25 e^{- 0.04 x}

Add a constant to the solution

= - 25 e^{- 0.04 x} + C

x \to 500 lim (e^{x})

\int_{2}^{\infty} \frac{1}{x ^{2} + x} d x

\frac{d}{d x} (x^{2} lo g_{e} (x))

\int \frac{x - 3}{x ^{2} + 49} d x

x \to 0 lim (\frac{x}{arctan ( x )})

What is the integral of e^{-0.04x} ?
The integral of e^{-0.04x} is -25e^{-0.04x}+C