What is the derivative of y=-2(x+1)^2-4 ?

The derivative of y=-2(x+1)^2-4 is -4x-4

What is the first derivative of y=-2(x+1)^2-4 ?

The first derivative of y=-2(x+1)^2-4 is -4x-4

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derivative of

y = - 2 (x + 1)^{2} - 4

- 4 x - 4

Solution steps

\frac{d}{d x} (- 2 (x + 1)^{2} - 4)

Simplify

- 2 (x + 1)^{2} - 4 : - 2 x^{2} - 4 x - 6

= \frac{d}{d x} (- 2 x^{2} - 4 x - 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (4 x) - \frac{d}{d x} (6)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (6) = 0

= - 4 x - 4 - 0

Simplify

= - 4 x - 4

x \to 4 + lim (\frac{3}{x ^{2} - 16})

\frac{\partial}{\partial x} (4 e^{x y + 2})

\frac{( 2 s + 6 )}{s ^{2} + 9}

f (x) = - 8 x^{3} - 52 x^{2} + 3

\frac{d y}{d x} = 2 y + x

What is the derivative of y=-2(x+1)^2-4 ?
The derivative of y=-2(x+1)^2-4 is -4x-4
What is the first derivative of y=-2(x+1)^2-4 ?
The first derivative of y=-2(x+1)^2-4 is -4x-4