What is the derivative of (2x^3)/3-12x ?

The derivative of (2x^3)/3-12x is 2x^2-12

What is the first derivative of (2x^3)/3-12x ?

The first derivative of (2x^3)/3-12x is 2x^2-12

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derivative of

\frac{2 x ^{3}}{3} - 12 x

2 x^{2} - 12

Solution steps

\frac{d}{d x} (\frac{2 x ^{3}}{3} - 12 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{2 x ^{3}}{3}) - \frac{d}{d x} (12 x)

\frac{d}{d x} (\frac{2 x ^{3}}{3}) = 2 x^{2}

\frac{d}{d x} (12 x) = 12

= 2 x^{2} - 12

\frac{d}{d x} (\frac{x ^{2}}{x + 5})

f (x) = 5 x^{4}

x \to 0 lim (\frac{2 + x}{2 - x})

\frac{d}{d x} (x (2 x - 1) (3 x + 2))

\int \frac{tan ^{3} ( ln ( x ) )}{9 x} d x

What is the derivative of (2x^3)/3-12x ?
The derivative of (2x^3)/3-12x is 2x^2-12
What is the first derivative of (2x^3)/3-12x ?
The first derivative of (2x^3)/3-12x is 2x^2-12