What is (\partial)/(\partial x)(x+ln(y)) ?

The answer to (\partial)/(\partial x)(x+ln(y)) is 1

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(\partial)/(\partial x)(x+ln(y))

\frac{\partial}{\partial x} (x + ln (y))

1

Solution steps

\frac{\partial}{\partial x} (x + ln (y))

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (ln (y))

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (ln (y)) = 0

= 1 + 0

Simplify

= 1

y^{^{'}} - y = 6 t e^{2 t}, y (0) = 1

x \to 0 lim (x^{2} \cdot e^{- x})

\frac{d}{d x} (\frac{1}{3} x^{\frac{3}{2}} - x^{\frac{1}{2}})

\frac{d y}{d x} + 6 y = 9

\int_{0}^{5} x^{2} (x - 5)^{4} d x

What is (\partial)/(\partial x)(x+ln(y)) ?
The answer to (\partial)/(\partial x)(x+ln(y)) is 1