What is the solution for f^'(x)=x^3-5x^2+3 ?

The solution for f^'(x)=x^3-5x^2+3 is f(x)=(x^4)/4-(5x^3)/3+3x+c_{1}

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f^'(x)=x^3-5x^2+3

f^{^{'}} (x) = x^{3} - 5 x^{2} + 3

f (x) = \frac{x ^{4}}{4} - \frac{5 x ^{3}}{3} + 3 x + c_{1}

Solution steps

f^{'} (x) = x^{3} - 5 x^{2} + 3

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int x^{3} - 5 x^{2} + 3 d x

\int x^{3} - 5 x^{2} + 3 d x = \frac{x ^{4}}{4} - \frac{5 x ^{3}}{3} + 3 x + c_{1}

f (x) = \frac{x ^{4}}{4} - \frac{5 x ^{3}}{3} + 3 x + c_{1}

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What is the solution for f^'(x)=x^3-5x^2+3 ?
The solution for f^'(x)=x^3-5x^2+3 is f(x)=(x^4)/4-(5x^3)/3+3x+c_{1}