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Popular >

integral of 1/(-y^2)

Solution

\int \frac{1}{- y ^{2}} d y

Solution

\frac{1}{y} + C

Solution steps

\int \frac{1}{- y ^{2}} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{1}{y ^{2}} d y

Apply the Power Rule

: - \frac{1}{y}

= - (- \frac{1}{y})

Simplify

= \frac{1}{y}

Add a constant to the solution

= \frac{1}{y} + C

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\int_{0}^{8} π (x - 1)^{2} d x

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\int (sin (x))^{2} x + (cos (x))^{2} x d x

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Frequently Asked Questions (FAQ)

What is the integral of 1/(-y^2) ?
The integral of 1/(-y^2) is 1/y+C