What is the integral of 3/(\sqrt[3]{x^2)} ?

The integral of 3/(\sqrt[3]{x^2)} is 9\sqrt[3]{x}+C

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integral of 3/(\sqrt[3]{x^2)}

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

assuming

x \geq 0

= 3 \cdot \int \frac{1}{x ^{\frac{2}{3}}} d x

Apply the Power Rule

: 3 x^{\frac{1}{3}}

= 3 \cdot 3 x^{\frac{1}{3}}

Simplify

Add a constant to the solution

x \to 1 - lim ((x - 1)^{2})

\int x^{2} (1 + 2 x^{3})^{5} d x

\frac{d}{d x} (x^{2} (x + 7)^{3})

\int \frac{1}{x ^{2} ( x ^{2} + 1 )} d x

\frac{d}{d x} (\frac{x}{2} - \frac{2}{x})

What is the integral of 3/(\sqrt[3]{x^2)} ?
The integral of 3/(\sqrt[3]{x^2)} is 9\sqrt[3]{x}+C