What is the derivative of (x+1(x-1)) ?

The derivative of (x+1(x-1)) is 2x

What is the first derivative of (x+1(x-1)) ?

The first derivative of (x+1(x-1)) is 2x

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\frac{d}{d x} ((x + 1) (x - 1))

2 x

Solution steps

\frac{d}{d x} ((x + 1) (x - 1))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x + 1, g = x - 1

= \frac{d}{d x} (x + 1) (x - 1) + \frac{d}{d x} (x - 1) (x + 1)

\frac{d}{d x} (x + 1) = 1

\frac{d}{d x} (x - 1) = 1

= 1 \cdot (x - 1) + 1 \cdot (x + 1)

Simplify

1 \cdot (x - 1) + 1 \cdot (x + 1) : 2 x

= 2 x

77 p + 20 - 360, at 75

\frac{d}{d x} (arctan (3 x + 2))

\frac{1}{5 + 2 x}

f (t) = \frac{5 t + 300}{t ^{2} + 25}

\int \frac{2 e ^{2 x}}{e ^{2 x} + 8 e ^{x} + 15} d x

What is the derivative of (x+1(x-1)) ?
The derivative of (x+1(x-1)) is 2x
What is the first derivative of (x+1(x-1)) ?
The first derivative of (x+1(x-1)) is 2x