What is laplacetransform 5*i(t) ?

The answer to laplacetransform 5*i(t) is (5i)/(s^2)

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laplacetransform 5*i(t)

laplace transform

5 \cdot i (t)

\frac{5 i}{s ^{2}}

Solution steps

L {5 i (t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 5 i L {t}

L {t} : \frac{1}{s ^{2}}

= 5 i \frac{1}{s ^{2}}

Refine

5 i \frac{1}{s ^{2}} : \frac{5 i}{s ^{2}}

= \frac{5 i}{s ^{2}}

\frac{x ^{\frac{1}{3}} - 4}{x ^{\frac{7}{2}}}

y^{^{''}} + 10 y^{^{'}} + 25 y = - 50 e^{- 5 x}

\int \frac{e ^{x}}{( e ^{x} - 5 ) ( e ^{x} - 11 )} d x

\int_{2}^{6} (x^{2} - 7 x + 6) d x

\int \frac{2 p ^{3}}{e ^{p}} d p

What is laplacetransform 5*i(t) ?
The answer to laplacetransform 5*i(t) is (5i)/(s^2)