What is the derivative of x^3+x ?

The derivative of x^3+x is 3x^2+1

What is the first derivative of x^3+x ?

The first derivative of x^3+x is 3x^2+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

x^{3} + x

3 x^{2} + 1

Solution steps

\frac{d}{d x} (x^{3} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d x}{d x}

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d x}{d x} = 1

= 3 x^{2} + 1

\int \frac{x ^{2} - 1}{( x - 3 ) ( x - 2 ) ^{2}} d x

\frac{d}{d x} (\frac{4 x}{x ^{2} + 2})

\frac{\partial}{\partial x} (x y - z^{2})

\int (8 - \frac{( 5 ^{x} )}{2}) d x

\int \frac{z ( 1 - z )}{( z + 1 ) ( z ^{2} + 1 ) ^{2}} d z