What is the limit as x approaches 0+of ln(2x) ?

The limit as x approaches 0+of ln(2x) is -infinity

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limit as x approaches 0+of ln(2x)

x \to 0 + lim (ln (2 x))

- \infty

Solution steps

x \to 0 + lim (ln (2 x))

Apply the Limit Chain Rule:

- \infty

= - \infty

\frac{d y}{d t} + y = 5 sin (2 t)

\frac{d}{d x} (- 3 x + 1)

\frac{( 1 + e ^{x} )}{1 - e ^{x}}

x \to - 2 lim ((3 x - 8)^{2})

(2 y + 2 y x) \frac{d y}{d x} = 1 - y^{2}

What is the limit as x approaches 0+of ln(2x) ?
The limit as x approaches 0+of ln(2x) is -infinity