What is the limit as x approaches+0 of ln(x^2) ?

The limit as x approaches+0 of ln(x^2) is Does not exist

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limit as x approaches+0 of ln(x^2)

x \to + 0 lim (ln (x^{2}))

Does not exist

Solution steps

x \to 0 lim (ln (x^{2}))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (ln (x^{2})) = - \infty

x \to 0 - lim (ln (x^{2})) =

Does not exist

= Does not exist

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What is the limit as x approaches+0 of ln(x^2) ?
The limit as x approaches+0 of ln(x^2) is Does not exist