What is the solution for (2xy+2x^3y)dx-(1+x^2)dy=0 ?

The solution for (2xy+2x^3y)dx-(1+x^2)dy=0 is y=e^{x^2+c_{1}}

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(2xy+2x^3y)dx-(1+x^2)dy=0

(2 x y + 2 x^{3} y) d x - (1 + x^{2}) d y = 0

y = e^{x^{2} + c_{1}}

Solution steps

(2 x y + 2 x^{3} y) d x - (1 + x^{2}) d y = 0

Solve separable ODE:

y = e^{x^{2} + c_{1}}

y = e^{x^{2} + c_{1}}

x \to \infty lim (a x^{4} + b x^{2} + c)

x \to 0 lim (\frac{3 x - 1}{2 x})

\int_{0}^{1} \frac{ln ( x )}{x} d x

\frac{\partial}{\partial x} (s cos (t))

\int \frac{1}{x ^{4} x ^{2} - 3} d x

What is the solution for (2xy+2x^3y)dx-(1+x^2)dy=0 ?
The solution for (2xy+2x^3y)dx-(1+x^2)dy=0 is y=e^{x^2+c_{1}}