What is the derivative of 2cos(4x) ?

The derivative of 2cos(4x) is -8sin(4x)

What is the first derivative of 2cos(4x) ?

The first derivative of 2cos(4x) is -8sin(4x)

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\frac{d}{d x} (2 cos (4 x))

- 8 sin (4 x)

Solution steps

\frac{d}{d x} (2 cos (4 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (cos (4 x))

Apply the chain rule:

- sin (4 x) \frac{d}{d x} (4 x)

= - sin (4 x) \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= 2 (- sin (4 x) \cdot 4)

Simplify

= - 8 sin (4 x)

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What is the derivative of 2cos(4x) ?
The derivative of 2cos(4x) is -8sin(4x)
What is the first derivative of 2cos(4x) ?
The first derivative of 2cos(4x) is -8sin(4x)