What is the solution for y^{'''}-y^{''}-y^'=0 ?

The solution for y^{'''}-y^{''}-y^'=0 is y=c_{1}+c_{2}e^{((1+sqrt(5))t)/2}+c_{3}e^{((1-sqrt(5))t)/2}

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y^{'''}-y^{''}-y^'=0

y^{^{'''}} - y^{^{''}} - y^{^{'}} = 0

y = c_{1} + c_{2} e^{\frac{( 1 + 5 ) t}{2}} + c_{3} e^{\frac{( 1 - 5 ) t}{2}}

Solution steps

y^{'''} (t) - y^{''} (t) - y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{\frac{( 1 + 5 ) t}{2}} + c_{3} e^{\frac{( 1 - 5 ) t}{2}}

y = c_{1} + c_{2} e^{\frac{( 1 + 5 ) t}{2}} + c_{3} e^{\frac{( 1 - 5 ) t}{2}}

\int 7 x e^{2 x} d x

x \to π lim ((x + π) csc (x))

f (x) = \frac{z - 5}{z + 5}

\int \frac{x ^{3} e ^{x^{2}}}{( x ^{2} + 1 ) ^{2}} d x

f (t) = t e^{4 t}

What is the solution for y^{'''}-y^{''}-y^'=0 ?
The solution for y^{'''}-y^{''}-y^'=0 is y=c_{1}+c_{2}e^{((1+sqrt(5))t)/2}+c_{3}e^{((1-sqrt(5))t)/2}