What is the integral from-infinity to 0 of xe^{5x} ?

The integral from-infinity to 0 of xe^{5x} is -1/25

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integral from-infinity to 0 of xe^{5x}

\int_{- \infty}^{0} x e^{5 x} d x

- \frac{1}{25}

Decimal Notation

- 0.04

Solution steps

\int_{- \infty}^{0} x e^{5 x} d x

Compute the indefinite integral:

\int x e^{5 x} d x = \frac{1}{25} (e^{5 x} \cdot 5 x - e^{5 x}) + C

Compute the boundaries:

\int_{- \infty}^{0} x e^{5 x} d x = - \frac{1}{25} - 0

= - \frac{1}{25} - 0

Simplify

= - \frac{1}{25}

y = 5 x + 11

n = 2 \sum \infty \frac{e ^{n}}{n !}

\int \frac{3}{x ( x ^{4} + 4 )} d x

\frac{d}{d x} (x ln (\frac{x}{5}))

\frac{d}{d x} ((1 + x)^{x})

What is the integral from-infinity to 0 of xe^{5x} ?
The integral from-infinity to 0 of xe^{5x} is -1/25