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Popular >

y^'+x^{-1}y=2xy^2

Solution

y^{^{'}} + x^{- 1} y = 2 x y^{2}

Solution

y = \frac{1}{x ( - 2 x + c _{1} )}

Solution steps

y^{'} (x) + x^{- 1} y = 2 x y^{2}

Solve Bernoulli ODE:

y = \frac{1}{x ( - 2 x + c _{1} )}

y = \frac{1}{x ( - 2 x + c _{1} )}

Popular Examples

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x \to \frac{25}{9} lim (3 \frac{x ^{2}}{2})

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\int \frac{tan ( x )}{cos ( x )} d x

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x \to 4 lim (9 \cdot 27)

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x \to - 1 lim (x - ln (- x - 1))

simplify arctan(y/x)simplify

arctan (\frac{y}{x})

Frequently Asked Questions (FAQ)

What is the solution for y^'+x^{-1}y=2xy^2 ?
The solution for y^'+x^{-1}y=2xy^2 is y= 1/(x(-2x+c_{1))}