What is the integral of (2-sqrt(t))/(t^2) ?

The integral of (2-sqrt(t))/(t^2) is -2/t+2/(sqrt(t))+C

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integral of (2-sqrt(t))/(t^2)

\int \frac{2 - t}{t ^{2}} d t

- \frac{2}{t} + \frac{2}{t} + C

Solution steps

\int \frac{2 - t}{t ^{2}} d t

Expand

\frac{2 - t}{t ^{2}} : \frac{2}{t ^{2}} - \frac{1}{t ^{\frac{3}{2}}}

= \int \frac{2}{t ^{2}} - \frac{1}{t ^{\frac{3}{2}}} d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{2}{t ^{2}} d t - \int \frac{1}{t ^{\frac{3}{2}}} d t

\int \frac{2}{t ^{2}} d t = - \frac{2}{t}

\int \frac{1}{t ^{\frac{3}{2}}} d t = - \frac{2}{t}

= - \frac{2}{t} - (- \frac{2}{t})

Simplify

= - \frac{2}{t} + \frac{2}{t}

Add a constant to the solution

= - \frac{2}{t} + \frac{2}{t} + C

x \to - \infty lim (\frac{( x ^{2} - 5 x )}{x - 2})

\frac{d y}{d x} = 1 - 2 x

\int x arctan (2 x) d x

\frac{d}{d x} (\frac{1 - cos ( x )}{sin ( x )})

\frac{\partial}{\partial x} (y + \frac{x ^{2}}{y})

What is the integral of (2-sqrt(t))/(t^2) ?
The integral of (2-sqrt(t))/(t^2) is -2/t+2/(sqrt(t))+C