What is inverse oflaplace (50000)/(s^2) ?

The answer to inverse oflaplace (50000)/(s^2) is 50000t

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inverse oflaplace (50000)/(s^2)

inverse laplace

\frac{50000}{s ^{2}}

50000 t

Solution steps

L^{- 1} {\frac{50000}{s ^{2}}}

= L^{- 1} {50000 \cdot \frac{1}{s ^{2}}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 50000 L^{- 1} {\frac{1}{s ^{2}}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{( n ) !}{s ^{n + 1}}} = t^{n}

L^{- 1} {\frac{1}{s ^{2}}} = t

= 50000 t

\int_{0}^{1} \frac{x ^{2}}{x + 1} d x

x y^{2} d x = d y - x d x, y (0) = - 1

\frac{d x}{d y}

\int \frac{x ^{2}}{1 - x} d x

θ^{^{''}} + \frac{4 k}{3} θ = 0

What is inverse oflaplace (50000)/(s^2) ?
The answer to inverse oflaplace (50000)/(s^2) is 50000t