What is the derivative of (x-y^2) ?

The derivative of (x-y^2) is 2(x-y)(1-(dy)/(dx))

What is the first derivative of (x-y^2) ?

The first derivative of (x-y^2) is 2(x-y)(1-(dy)/(dx))

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\frac{d}{d x} ((x - y)^{2})

2 (x - y) (1 - \frac{d y}{d x})

Solution steps

\frac{d}{d x} ((x - y)^{2})

Apply the chain rule:

2 (x - y) \frac{d}{d x} (x - y)

= 2 (x - y) \frac{d}{d x} (x - y)

\frac{d}{d x} (x - y) = 1 - \frac{d y}{d x}

= 2 (x - y) (1 - \frac{d y}{d x})

4 x - 17

\int \frac{cos ^{2} ( 4 x )}{4} d x

\frac{1}{s} \cdot (\frac{10}{s ^{2} + s + 10})

- 4 e^{3 t}

x \to 0 lim (- 9 x^{2} + 6 x)

What is the derivative of (x-y^2) ?
The derivative of (x-y^2) is 2(x-y)(1-(dy)/(dx))
What is the first derivative of (x-y^2) ?
The first derivative of (x-y^2) is 2(x-y)(1-(dy)/(dx))