What is maclaurin f(x)=(2x-1)^2 ?

The answer to maclaurin f(x)=(2x-1)^2 is 1-4x+4x^2

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maclaurin f(x)=(2x-1)^2

maclaurin

f (x) = (2 x - 1)^{2}

1 - 4 x + 4 x^{2}

Solution steps

Apply the Maclaurin Formula

= 1 + \frac{\frac{d}{d x} ( ( 2 x - 1 ) ^{2} ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( ( 2 x - 1 ) ^{2} ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( ( 2 x - 1 ) ^{2} ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 1 + \frac{- 4}{1 !} x + \frac{8}{2 !} x^{2} + \frac{0}{3 !} x^{3} + \frac{0}{4 !} x^{4} + \frac{0}{5 !} x^{5} + \frac{0}{6 !} x^{6} + \frac{0}{7 !} x^{7} + \frac{0}{8 !} x^{8} + \frac{0}{9 !} x^{9} + \frac{0}{10 !} x^{10}

Refine

= 1 - 4 x + 4 x^{2}

\int_{0}^{\frac{π}{4}} x^{3} cos (x) d x

\int x cos (x^{3}) d x

\int_{0}^{1} e^{6 x} d x

\int (3 y^{3} - 2 y^{2} + \frac{e ^{y}}{6}) d y

\frac{d}{d x} (\frac{- 2 x}{- 4 x ^{4}})

What is maclaurin f(x)=(2x-1)^2 ?
The answer to maclaurin f(x)=(2x-1)^2 is 1-4x+4x^2