What is the tangent of f(x)=x^2-7x+7,\at x=0 ?

The tangent of f(x)=x^2-7x+7,\at x=0 is y=-7x+7

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tangent of f(x)=x^2-7x+7,\at x=0

tangent of

f (x) = x^{2} - 7 x + 7, at x = 0

y = - 7 x + 7

Solution steps

Find the tangent point:

(0, 7)

Find the slope of

f (x) = x^{2} - 7 x + 7 : \frac{df ( x )}{d x} = 2 x - 7

Compute the slope of

f (x) = x^{2} - 7 x + 7

x = 0 : m = - 7

Find the line with slope m=

- 7

and passing through

(0, 7) : y = - 7 x + 7

y = - 7 x + 7

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What is the tangent of f(x)=x^2-7x+7,\at x=0 ?
The tangent of f(x)=x^2-7x+7,\at x=0 is y=-7x+7