What is the solution for xy(dx-dy)=x^2dy+y^2dx ?

The solution for xy(dx-dy)=x^2dy+y^2dx is y= x/(\W(\frac{x^2){c_{1}})}

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xy(dx-dy)=x^2dy+y^2dx

x y (d x - d y) = x^{2} d y + y^{2} d x

y = \frac{x}{W ( \frac{x ^{2}}{c _{1}} )}

Solution steps

x y (d x - d y) = x^{2} d y + y^{2} d x

Solve using substitution:

y = \frac{x}{W ( \frac{x ^{2}}{c _{1}} )}

y = \frac{x}{W ( \frac{x ^{2}}{c _{1}} )}

y^{^{''}} + 8 y^{^{'}} + 17 y = 0

\frac{d}{d x} ((x^{3} + 1) (x^{2} - 3 x))

\frac{d ^{2}}{d x ^{2}} (x^{2} - \frac{1}{x ^{2}})

\int_{0}^{4} 2^{x} d x

\frac{d}{d x} (2 x^{3} + 3)

What is the solution for xy(dx-dy)=x^2dy+y^2dx ?
The solution for xy(dx-dy)=x^2dy+y^2dx is y= x/(\W(\frac{x^2){c_{1}})}