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Popular >

xy^'+y=xe^x

Solution

x y^{^{'}} + y = x e^{x}

Solution

y = e^{x} - \frac{e ^{x}}{x} + \frac{c _{1}}{x}

Solution steps

x y^{'} (x) + y = x e^{x}

Solve linear ODE:

y = e^{x} - \frac{e ^{x}}{x} + \frac{c _{1}}{x}

y = e^{x} - \frac{e ^{x}}{x} + \frac{c _{1}}{x}

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\int 5^{u} d u

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\int ln (x^{2} + 2) d x

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\int 17 sin^{2} (x co) s^{2} x d x

Frequently Asked Questions (FAQ)

What is the solution for xy^'+y=xe^x ?
The solution for xy^'+y=xe^x is y=e^x-(e^x)/x+(c_{1})/x