What is the derivative of 2ln(x+1) ?

The derivative of 2ln(x+1) is 2/(x+1)

What is the first derivative of 2ln(x+1) ?

The first derivative of 2ln(x+1) is 2/(x+1)

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derivative of

2 ln (x + 1)

\frac{2}{x + 1}

Solution steps

\frac{d}{d x} (2 ln (x + 1))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (ln (x + 1))

Apply the chain rule:

\frac{1}{x + 1} \frac{d}{d x} (x + 1)

= \frac{1}{x + 1} \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= 2 \cdot \frac{1}{x + 1} \cdot 1

Simplify

2 \cdot \frac{1}{x + 1} \cdot 1 : \frac{2}{x + 1}

= \frac{2}{x + 1}

n = 1 \sum \infty \frac{n !}{10 7 ^{n}}

\frac{d}{d x} (x^{3} + x y^{2} e^{\frac{x}{y}})

- y^{^{''}} - y + x^{2} = 0

x \to \infty lim (\frac{3 x}{2})

\int \frac{x ^{2} - x + 18}{x ^{3} + 3 x} d x

What is the derivative of 2ln(x+1) ?
The derivative of 2ln(x+1) is 2/(x+1)
What is the first derivative of 2ln(x+1) ?
The first derivative of 2ln(x+1) is 2/(x+1)