What is the slope ofintercept (4,-1),(-1,-4) ?

The slope ofintercept (4,-1),(-1,-4) is y= 3/5 x-17/5

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slope ofintercept (4,-1),(-1,-4)

slope intercept

(4, - 1), (- 1, - 4)

y = \frac{3}{5} x - \frac{17}{5}

Solution steps

Compute the slope

(4, - 1), (- 1, - 4) : m = \frac{3}{5}

Compute the

y

intercept:

b = - \frac{17}{5}

Construct the line equation

y = mx + b

where

m = \frac{3}{5}

and

b = - \frac{17}{5}

y = \frac{3}{5} x - \frac{17}{5}

\frac{1}{s ^{2} + s ^{1} + s ^{1} + 1}

\int \frac{1}{u 5 - u ^{2}} d u

\int_{0}^{1} x^{4} (2 + 2 x^{5}) d x

\int (e^{x} + x^{e} - e x) d x

\frac{d ^{2}}{d x ^{2}} (x 1 - x^{2})

What is the slope ofintercept (4,-1),(-1,-4) ?
The slope ofintercept (4,-1),(-1,-4) is y= 3/5 x-17/5