What is the tangent of f(x)=2x+3/x ,\at x=-1 ?

The tangent of f(x)=2x+3/x ,\at x=-1 is y=-x-6

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tangent of f(x)=2x+3/x ,\at x=-1

tangent of

f (x) = 2 x + \frac{3}{x}, at x = - 1

y = - x - 6

Solution steps

Find the tangent point:

(- 1, - 5)

Find the slope of

f (x) = 2 x + \frac{3}{x} : \frac{df ( x )}{d x} = 2 - \frac{3}{x ^{2}}

Compute the slope of

f (x) = 2 x + \frac{3}{x}

x = - 1 : m = - 1

Find the line with slope m=

- 1

and passing through

(- 1, - 5) : y = - x - 6

y = - x - 6

\frac{\partial}{\partial x} (\frac{arctan ( \cdot y ^{2} )}{x})

\frac{d y}{d t} + e^{t} y = - e^{t}

2 y^{^{''}} + 3 y^{^{'}} + 9 y = 0

\frac{( x ^{4} - 5 x ^{3} + x )}{x ^{2}}

f (x) = (3 x^{2} - 2 x - 1)^{\frac{3}{2}}

What is the tangent of f(x)=2x+3/x ,\at x=-1 ?
The tangent of f(x)=2x+3/x ,\at x=-1 is y=-x-6