What is the derivative of ((x^4-5x^3+sqrt(x)))/(x^2) ?

The derivative of ((x^4-5x^3+sqrt(x)))/(x^2) is (4x^4-10x^3-3sqrt(x))/(2x^3)

What is the first derivative of ((x^4-5x^3+sqrt(x)))/(x^2) ?

The first derivative of ((x^4-5x^3+sqrt(x)))/(x^2) is (4x^4-10x^3-3sqrt(x))/(2x^3)

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derivative of

\frac{( x ^{4} - 5 x ^{3} + x )}{x ^{2}}

\frac{4 x ^{4} - 10 x ^{3} - 3 x}{2 x ^{3}}

Solution steps

\frac{d}{d x} (\frac{x ^{4} - 5 x ^{3} + x}{x ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{4} - 5 x ^{3} + x ) x ^{2} - \frac{d}{d x} ( x ^{2} ) ( x ^{4} - 5 x ^{3} + x )}{( x ^{2} ) ^{2}}

\frac{d}{d x} (x^{4} - 5 x^{3} + x) = 4 x^{3} - 15 x^{2} + \frac{1}{2 x}

\frac{d}{d x} (x^{2}) = 2 x

= \frac{( 4 x ^{3} - 15 x ^{2} + \frac{1}{2 x} ) x ^{2} - 2 x ( x ^{4} - 5 x ^{3} + x )}{( x ^{2} ) ^{2}}

Simplify

\frac{( 4 x ^{3} - 15 x ^{2} + \frac{1}{2 x} ) x ^{2} - 2 x ( x ^{4} - 5 x ^{3} + x )}{( x ^{2} ) ^{2}} : \frac{4 x ^{4} - 10 x ^{3} - 3 x}{2 x ^{3}}

= \frac{4 x ^{4} - 10 x ^{3} - 3 x}{2 x ^{3}}

f (x) = (3 x^{2} - 2 x - 1)^{\frac{3}{2}}

\int \frac{38}{38 + e ^{x}} d x

\int \frac{3 + u}{1 - u ^{2}} d u

What is the derivative of ((x^4-5x^3+sqrt(x)))/(x^2) ?
The derivative of ((x^4-5x^3+sqrt(x)))/(x^2) is (4x^4-10x^3-3sqrt(x))/(2x^3)
What is the first derivative of ((x^4-5x^3+sqrt(x)))/(x^2) ?
The first derivative of ((x^4-5x^3+sqrt(x)))/(x^2) is (4x^4-10x^3-3sqrt(x))/(2x^3)