What is the tangent of f(x)=x+3/x ,\at x=2 ?

The tangent of f(x)=x+3/x ,\at x=2 is y= 1/4 x+3

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tangent of f(x)=x+3/x ,\at x=2

tangent of

f (x) = x + \frac{3}{x}, at x = 2

y = \frac{1}{4} x + 3

Solution steps

Find the tangent point:

(2, \frac{7}{2})

Find the slope of

f (x) = x + \frac{3}{x} : \frac{df ( x )}{d x} = 1 - \frac{3}{x ^{2}}

Compute the slope of

f (x) = x + \frac{3}{x}

x = 2 : m = \frac{1}{4}

Find the line with slope m=

\frac{1}{4}

and passing through

(2, \frac{7}{2}) : y = \frac{1}{4} x + 3

y = \frac{1}{4} x + 3

E

f (x) = e^{- x} - e^{- x} x

x \to 3 + lim (\frac{x + 1}{x - 3})

\frac{\partial}{\partial x} (26 sin (z) x y)

\int cos (x) \cdot e^{x} d x

What is the tangent of f(x)=x+3/x ,\at x=2 ?
The tangent of f(x)=x+3/x ,\at x=2 is y= 1/4 x+3