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Popular >

y^'=x+y,y(0)=4

Solution

y^{^{'}} = x + y, y (0) = 4

Solution

y = - x - 1 + 5 e^{x}

Solution steps

y^{'} (x) = x + y

Solve linear ODE:

y = - x - 1 + 5 e^{x}

y = - x - 1 + 5 e^{x}

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\int_{1}^{3} 8^{x} - 2^{x} d x

slope of (3,1),(-2,-1)slope

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Frequently Asked Questions (FAQ)

What is the solution for y^'=x+y,y(0)=4 ?
The solution for y^'=x+y,y(0)=4 is y=-x-1+5e^x