What is the solution for xy+y^2-x^2(dy)/(dx)=0 ?

The solution for xy+y^2-x^2(dy)/(dx)=0 is y= x/(-ln(x)+c_{1)}

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xy+y^2-x^2(dy)/(dx)=0

x y + y^{2} - x^{2} \frac{d y}{d x} = 0

y = \frac{x}{- ln ( x ) + c _{1}}

Solution steps

x y + y^{2} - x^{2} \frac{d y}{d x} = 0

Solve Bernoulli ODE:

y = \frac{x}{- ln ( x ) + c _{1}}

y = \frac{x}{- ln ( x ) + c _{1}}

\int_{1}^{2} 11 4 x^{2} - 3 d x

\frac{1}{( s ^{2} + 1 ) ( s ^{2} - 6 )}

f (x) = (e^{x} + 1)^{7 x}

\frac{4}{s} + \frac{6}{s ^{2}} - \frac{1}{s + 8}

\frac{d}{d x} (\frac{cos ( x ) e ^{x}}{tan ( x )})

What is the solution for xy+y^2-x^2(dy)/(dx)=0 ?
The solution for xy+y^2-x^2(dy)/(dx)=0 is y= x/(-ln(x)+c_{1)}