What is the first derivative of ax+b ?

The first derivative of ax+b is a

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derivative of ax+b

\frac{d}{d x} (a x + b)

a

Solution steps

\frac{d}{d x} (a x + b)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a x) + \frac{d b}{d x}

\frac{d}{d x} (a x) = a

\frac{d b}{d x} = 0

= a + 0

Simplify

= a

\frac{d}{d x} ((- 2 cos (2 x) - sin (3 x) - 3)^{2})

\int x^{- n} d x

y = (2 lo g_{e} (x) - 3)^{4}

\int \frac{( 7 x + 29 )}{x ^{2} + 8 x + 15} d x

x^{\frac{9}{5}}