What is the derivative of (x^3+7)e^x ?

The derivative of (x^3+7)e^x is 3x^2e^x+e^x(x^3+7)

What is the first derivative of (x^3+7)e^x ?

The first derivative of (x^3+7)e^x is 3x^2e^x+e^x(x^3+7)

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derivative of

(x^{3} + 7) e^{x}

3 x^{2} e^{x} + e^{x} (x^{3} + 7)

Solution steps

\frac{d}{d x} ((x^{3} + 7) e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{3} + 7, g = e^{x}

= \frac{d}{d x} (x^{3} + 7) e^{x} + \frac{d}{d x} (e^{x}) (x^{3} + 7)

\frac{d}{d x} (x^{3} + 7) = 3 x^{2}

\frac{d}{d x} (e^{x}) = e^{x}

= 3 x^{2} e^{x} + e^{x} (x^{3} + 7)

f (x) = - 1 x^{- \frac{3}{5}}

\frac{d}{d x} (cos (\frac{x}{y}))

\frac{d}{d a} (2 sin (2 a) + 2 cos^{2} (a))

\frac{2}{s + 1} + \frac{16 s}{s ^{2} + 9}

(1.4) (3.5)

What is the derivative of (x^3+7)e^x ?
The derivative of (x^3+7)e^x is 3x^2e^x+e^x(x^3+7)
What is the first derivative of (x^3+7)e^x ?
The first derivative of (x^3+7)e^x is 3x^2e^x+e^x(x^3+7)