What is (\partial)/(\partial x)(0.1*y^2+0.05*x*y) ?

The answer to (\partial)/(\partial x)(0.1*y^2+0.05*x*y) is 0.05y

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(0.1y^2+0.05x*y)

\frac{\partial}{\partial x} (0.1 \cdot y^{2} + 0.05 \cdot x \cdot y)

0.05 y

Solution steps

\frac{\partial}{\partial x} (0.1 y^{2} + 0.05 x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (0.1 y^{2}) + \frac{\partial}{\partial x} (0.05 x y)

\frac{\partial}{\partial x} (0.1 y^{2}) = 0

\frac{\partial}{\partial x} (0.05 x y) = 0.05 y

= 0 + 0.05 y

Simplify

= 0.05 y

\int (sec (x)) d x

\frac{d}{d x} (arcsin (6 x))

\frac{d}{d x} (3 arcsinh (tan (x)))

cos (- 5 x)

\int sec^{3} (1) d x

What is (\partial)/(\partial x)(0.1*y^2+0.05*x*y) ?
The answer to (\partial)/(\partial x)(0.1*y^2+0.05*x*y) is 0.05y