What is the limit as x approaches-infinity of-4e^x ?

The limit as x approaches-infinity of-4e^x is 0

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limit as x approaches-infinity of-4e^x

x \to - \infty lim (- 4 e^{x})

0

Solution steps

x \to - \infty lim (- 4 e^{x})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= - 4 \cdot x \to - \infty lim (e^{x})

Apply the common limit:

x \to - \infty lim (e^{x}) = 0

= - 4 \cdot 0

Simplify

= 0

y = ln (x^{2} - 3 x + 1), (3, 0)

y^{^{'}} = \frac{x - y sin ( 2 x )}{sin ^{2} ( x )}

f (x) = 3 sin^{2} (x)

y^{^{''}} + 9 y = t^{2} + cos (3 t)

\frac{s - 5}{s ^{2} + 4 s + 20}

What is the limit as x approaches-infinity of-4e^x ?
The limit as x approaches-infinity of-4e^x is 0