What is the integral from-1 to 0.5 of 1.5x^2 ?

The integral from-1 to 0.5 of 1.5x^2 is 0.5625

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integral from-1 to 0.5 of 1.5x^2

\int_{- 1}^{0.5} 1.5 x^{2} d x

0.5625

Solution steps

\int_{- 1}^{0.5} 1.5 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 1.5 \cdot \int_{- 1}^{0.5} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{- 1}^{0.5}

= 1.5 [\frac{x ^{3}}{3}]_{- 1}^{0.5}

Simplify

= 1.5 [0.33333 \dots x^{3}]_{- 1}^{0.5}

Compute the boundaries:

0.375

= 1.5 \cdot 0.375

Simplify

= 0.5625

\int \frac{x ^{3} - 4 x - 10}{x ^{3} - 3 x ^{2} - 4 x + 12} d x

(x^{2} - 1)^{^{'}}

\int \frac{x}{2 x ^{2} - 1} d x

\frac{d y}{d x} - (\frac{4}{x}) y = x^{5} e^{x}

x \to 2 lim (\frac{x ^{2} - 2}{\frac{5 x}{7} - \frac{5 2}{7}})

What is the integral from-1 to 0.5 of 1.5x^2 ?
The integral from-1 to 0.5 of 1.5x^2 is 0.5625