What is the solution for 1/(x^7)y^'=15+12y ?

The solution for 1/(x^7)y^'=15+12y is y=(e^{(3x^8+c_{1})/2})/(4)-5/4

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1/(x^7)y^'=15+12y

\frac{1}{x ^{7}} y^{^{'}} = 15 + 12 y

y = \frac{e ^{\frac{3 x ^{8} + c _{1}}{2}}}{4} - \frac{5}{4}

Solution steps

\frac{1}{x ^{7}} y^{'} (x) = 15 + 12 y

Solve separable ODE:

y = \frac{e ^{\frac{3 x ^{8} + c _{1}}{2}}}{4} - \frac{5}{4}

y = \frac{e ^{\frac{3 x ^{8} + c _{1}}{2}}}{4} - \frac{5}{4}

x \to 2 lim (\frac{x - 2}{x - 1})

\frac{d}{d x} (ln (1 + \frac{3}{x}))

(x^{2} + 1) y^{^{'}} = - 4 x (y - 1), y (0) = 8

\int 4 e^{5} d x

x \to 0 lim (\frac{e ^{\frac{1}{x}}}{x})

What is the solution for 1/(x^7)y^'=15+12y ?
The solution for 1/(x^7)y^'=15+12y is y=(e^{(3x^8+c_{1})/2})/(4)-5/4