What is the solution for (tdy)/(dt)=y+5t^2sin(t) ?

The solution for (tdy)/(dt)=y+5t^2sin(t) is y=-5cos(t)t+c_{1}t

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(tdy)/(dt)=y+5t^2sin(t)

\frac{t d y}{d t} = y + 5 t^{2} sin (t)

y = - 5 cos (t) t + c_{1} t

Solution steps

\frac{t d y}{d t} = y + 5 t^{2} sin (t)

Solve linear ODE:

y = - 5 cos (t) t + c_{1} t

y = - 5 cos (t) t + c_{1} t

\frac{d}{d x} ((x - 2)^{3} (x^{2} + 9)^{4})

\frac{d}{d x} (\frac{3 a ^{2}}{x ^{2}} - \frac{a}{3 x ^{4}})

f (x) = 24 x

\frac{d}{d x} (- \frac{10}{x ^{11}})

\int e^{x} + 1 d x

What is the solution for (tdy)/(dt)=y+5t^2sin(t) ?
The solution for (tdy)/(dt)=y+5t^2sin(t) is y=-5cos(t)t+c_{1}t