What is the integral of 1/(sqrt(1-x^2)arcsin(x)) ?

The integral of 1/(sqrt(1-x^2)arcsin(x)) is ln|arcsin(x)|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/(sqrt(1-x^2)arcsin(x))

\int \frac{1}{1 - x ^{2} arcsin ( x )} d x

ln ∣ arcsin (x) ∣ + C

Solution steps

\int \frac{1}{1 - x ^{2} arcsin ( x )} d x

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = arcsin (x)

= ln ∣ arcsin (x) ∣

Add a constant to the solution

= ln ∣ arcsin (x) ∣ + C

\frac{\partial}{\partial y} (x^{2} + yz)

\frac{d}{d x} (ln (h + \frac{1}{2 a x ^{2}} + b))

x \to 0 lim (\frac{1 - cos ( 5 x )}{sin ( 3 x )})

3 \frac{d r}{d s} = e^{r - 2 s}

(x, y) \to (4, 2) lim (6 x + 3 y)

What is the integral of 1/(sqrt(1-x^2)arcsin(x)) ?
The integral of 1/(sqrt(1-x^2)arcsin(x)) is ln|arcsin(x)|+C